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(-4)=4F^2-5F+6
We move all terms to the left:
(-4)-(4F^2-5F+6)=0
We add all the numbers together, and all the variables
-(4F^2-5F+6)-4=0
We get rid of parentheses
-4F^2+5F-6-4=0
We add all the numbers together, and all the variables
-4F^2+5F-10=0
a = -4; b = 5; c = -10;
Δ = b2-4ac
Δ = 52-4·(-4)·(-10)
Δ = -135
Delta is less than zero, so there is no solution for the equation
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